## Table of Contents

#### Exercise 9.2 class 8 solution-Introduction

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Exercise 9.2 class 8 solution- area of quadrilaterals

The area of a quadrilateral can be calculated in various ways, depending on the type of quadrilateral and the information provided. Here are some common methods for finding the area of different types of quadrilaterals:

1.**Rectangle or Square:**

- The area of a rectangle or square is given by the formula:
`Area = Length × Width`

. - For a square, where all sides are equal, you can also use:
`Area = Side × Side`

.

2.**Parallelogram:**

- The area of a parallelogram is given by the formula:
`Area = Base × Height`

, where the base is one of the sides, and the height is the perpendicular distance between the two bases.

**Trapezoid:**

- The area of a trapezoid is calculated using the formula:
`Area = (1/2) × (Sum of the lengths of the parallel sides) × Height`

.

**Rhombus**

- The area of a rhombus can be found using the formula:

`Area = (Diagonal 1 × Diagonal 2) / 2`

, where the diagonals are the line segments connecting opposite corners.

**General Quadrilateral:**

- For a general quadrilateral (not specifically defined as one of the above types), you can use the
**Heron’s Formula**if you know the lengths of all four sides and the semiperimeter:- Calculate the semiperimeter (s) as:
`s = (a + b + c + d) / 2`

, where a, b, c, and d are the lengths of the four sides. - Then, use Heron’s Formula to find the area:
`Area = √(s × (s - a) × (s - b) × (s - c) × (s - d))`

.

- Calculate the semiperimeter (s) as:

For specific calculations, you’ll need to provide more details about the quadrilateral, such as the type of quadrilateral and the lengths of its sides, diagonals, or other relevant information.

#### Exercise 9.2 class 8 solution- Examples of area of quadrilateral

**Example 9.2.1. Find the area of rhombus is 120 cm square and one of its diagonal is 16 cm. find the length of other diagonal.**

**9.2.2. Find the area of a rhombus whose diagonals are of length 20cm and 8.2 cm.**

solve.

**Example 9.2.3. The area of trapezium shaped field is 480 meter square . the distance between two parallel side is 15m.if one of the parallel side is 20m .find the other parallel side .**

solve.

#### Exercise 9.2 class 8 solution- exercise preview

Our Exercise 9.2 Preview is designed to give you a taste of what’s in store. You’ll find a selection of math problems and questions that challenge your analytical and problem-solving skills. It’s a glimpse into the wonderful world of math exercises that will not only sharpen your mathematical prowess but also help you build the confidence you need to excel in your Class 8 studies.

#### Exercise 9.2 class 8 solution- solution pdf

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So, get ready to unlock the world of mathematics and explore Exercise 9.2 class 8 solutions that will help you not only in your exams but also in building a strong foundation for future mathematical adventures. Click, download, and excel in math! Your math journey is about to get a whole lot easier.

9.2Exercise 10.1 class 8 solution

Exercise 10.2 class 8 solution

Exercise 11.1 class 8 solution

Exercise 11.2 class 8 solution

Exercise 12.1 class 8 solution

Exercise 12.2 class 8 solution

Exercise 12.3 class 8 solution

Exercise 13.1 class 8 solution

Exercise 13.2 class 8 solution

Exercise 13.3 class 8 solution

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