Exercise 9.5 class 8 solution

Exercise 9.5 class 8 solution-Introduction

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Exercise 9.5 class 8 solution-Volume of cuboid ,cube and cylinder

Here are the formulas for calculating the volume of a cuboid, a cube, and a cylinder:

Volume of a Cuboid: The volume of a cuboid can be calculated using the formula:Volume = Length (L) × Width (W) × Height (H)
Volume of a Cube: The volume of a cube can be calculated by the formula:Volume = Side Length (S)³
Volume of a Cylinder: The volume of a cylinder can be calculated using the formula:Volume = πr²hWhere:
- ‘r’ is the radius of the circular base.
- ‘h’ is the height of the cylinder.

You can use these formulas to find the volume of a cuboid, a cube, or a cylinder, provided you have the necessary dimensions (length, width, height, side length, radius, and height). Simply plug in the values into the respective formulas to calculate the volume.

EXAMPLE 9.5.1 Find the volume of the cube having side 2.5 cm

solve.

EXAMPLE 9.5.2 A cuboid of dimension 60cm*54cm*30cm.how many small cubes of side 6cm can be placed in the given cuboid ?

solve.

Exercise 9.5 class 8 solution- Difference between volume and capacity

Volume and capacity are related concepts often used in the context of measuring the amount of space occupied by an object or the amount of substance something can hold. However, they have different applications and units of measurement:

Volume:

Volume is a measurement of the three-dimensional space occupied by an object or substance.
It is typically measured in cubic units, such as cubic centimeters (cm³) or cubic meters (m³), depending on the scale of measurement.
Volume is used to describe the physical dimensions of solids, liquids, or gases.
For example, the volume of a cube is calculated by multiplying its length, width, and height (Volume = Length × Width × Height).

Capacity:

Capacity is a measure of how much substance, typically a liquid or gas, a container or vessel can hold.
It is often measured in units like liters (L) or milliliters (mL) for liquids and cubic centimeters (cm³) for gases.
Capacity is commonly used when describing the size of containers, bottles, tanks, or any vessel designed to hold a specific quantity of material.
For example, the capacity of a water bottle might be 500 milliliters (500 mL), which means it can hold 500 milliliters of liquid.

In summary, volume is a measure of the amount of space occupied by an object, while capacity refers to the amount of substance a container can hold. The two concepts are closely related, but the choice of terms and units depends on the context and the nature of the material being measured.

EXAMPLE 9.5.3 A milk tank is in the form of a cylinder whose radius is 1.5m and length is 7m. find the quantity of milk in litres that can be stored in the tank ?

SOLVE.

Exercise 9.5 class 8 solution-Relation between cm and litres

The relationship between cubic centimeters (cm³) and liters (L) is based on the metric system of measurement. The liter is a unit of volume within the metric system, and the cubic centimeter is a sub unit of volume, often used for precise measurements. Here’s the conversion between the two:

1 liter (L) is equivalent to 1,000 cubic centimeters (cm³).

In other words, 1 liter contains 1,000 cubic centimeters.

For example:

2 liters = 2,000 cubic centimeters (2 L × 1,000 cm³/L)
500 cubic centimeters = 0.5 liters (500 cm³ ÷ 1,000 cm³/L)

Volume in liters (L) = Volume in cubic centimeters (cm³) / 1,000

For example, if you have a volume of 3,000 cubic centimeters, you can convert it to liters as follows:

Volume in liters (L) = 3,000 cm³ / 1,000 = 3 liters (L)

Exercise 9.5 class 8 solution- exercise preview

Our Exercise 9.5 Preview is designed to give you a taste of what’s in store. You’ll find a selection of math problems and questions that challenge your analytical and problem-solving skills. It’s a glimpse into the wonderful world of math exercises that will not only sharpen your mathematical prowess but also help you build the confidence you need to excel in your Class 8 studies.

Exercise 9.5 class 8 solution- solution pdf

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9.5

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