NCERT exercise 2.3 class 8 solution -students can click here to download the entire pdf chapterwise .here free pdf can be download for NCERT solution class 8. all Exercise ** **are available here. These solutions are available in downloadable PDF format as well. it will help students in getting rid of all the doubts about those particular topics that are covered in the exercise. The NCERT textbook provides plenty of questions for the students to solve and practise. Solving and practising is more than enough to score high in the Class 8 examinations. Moreover, students should make sure that they practise every problem given in the textbook . exercise 2.3 class 8 solution Pdf can be downloaded free here.

#### Exercise 2.3 class 8 solution-exercise preview

### Exercise 2.3 class 8 solution reducing equation to simplest form

Reducing an equation to its simplest form typically involves simplifying or eliminating common factors, combining like terms, and ensuring that the equation is in a clear, concise, and standard form. The exact steps you’ll take depend on the type of equation and the simplifications required. Here’s a general guide:

**Combine Like Terms:**In an equation with multiple terms, combine like terms on both sides. This usually involves addition or subtraction.**Distribute (if necessary):**If the equation contains parentheses, distribute any constants or variables to eliminate them.**Eliminate Fractions:**If your equation contains fractions or rational expressions, you may want to eliminate them. To do this, you can multiply both sides of the equation by the least common denominator to clear the fractions.**Eliminate Common Factors:**Look for common factors in the equation and eliminate them. This can involve dividing both sides of the equation by a common factor.**Isolate the Variable:**If your goal is to solve for a specific variable, isolate that variable on one side of the equation. This typically involves addition, subtraction, multiplication, or division to move terms to the other side.**Standard Form:**Ensure that your equation is in standard form. For linear equations, this means having the variable term on one side and constants on the other. For quadratic equations, it means having the equation set to zero.**Simplify Further (if needed):**Sometimes you may have the option to simplify the equation further, like combining constants or using properties of exponents or radicals.**Verify Solutions:**If you have solved the equation, plug your solution back into the original equation to verify that it works. Keep in mind that the specific steps and simplifications will vary depending on the type of equation you are working with. Linear, quadratic, rational, and trigonometric equations all have different techniques and considerations for simplification. Additionally, the goal of simplification may differ. In some cases, you may want to find a single value for a variable, while in others, you may be looking for a general solution or a specific relationship between variables.

### Exercise 2.3 class 8 solution –

here the pdf of Exercise 2.3 class 8 solution is given to help students.students can view as well as download the pdf from here of Exercise 2.3 class 8 solution

DocScanner-09-Oct-2023-11-33-pm### Exercise 2.3 class 8 solution-an example of reducing to lowest form

Let’s go through an example of simplifying a linear equation to its simplest form:

**Example:** Simplify the following linear equation to its simplest form:

(3x + 2) – (2x – 5) = 4 – (x + 3)

**Step 1:** Expand the expressions inside the parentheses:

3x + 2 – 2x + 5 = 4 – x – 3

**Step 2:** Combine like terms on both sides of the equation:

(x + 7) = (1 – x)

**Step 3:** Move variable terms to one side and constants to the other side:

x + x = 1 – 7

**Step 4:** Combine like terms again:

2x = -6

**Step 5:** Isolate the variable “x” by dividing both sides by 2:

2x) / 2 = (-6) / 2

x = -3

**Step 6:** Verify the solution by substituting it back into the original equation:

(3(-3) + 2) – (2(-3) – 5) = 4 – (-3 + 3)

(-9 + 2) – (-6 – 5) = 4 – 0

-7 + 11 = 4

4 = 4

The equation is true, so the solution x = -3 is correct. The equation has been simplified to its simplest form, and the solution has been verified.